Question

10 volts potential applied could prevent ejection of electron from a metal irradiatedwith a photon of 18 ev energy. what is the work function of the metal​

Answer 1

ANSWER

Here W=4eV which is the work function of the metal.

Now E=hν corresponds to the energy of the incident light if the energy of the incident light is greater than work function of the metal or if it overcomes the attractive forces between metal electrons then photoelectric effect takes place.

Here E=(6.63×10 −34 Js)(2.3×10 10^15Hz)=15.25×10-19J

In eV, E=9.5eV

Now E>W hence photoelectric effect will take place

K.E max =E−W=9.5eV−4eV=5.52eV

Stopping potential= eK.E ma =5.52V

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Answer 2

Given:

The stopping potential, V₀ = 10 V

The energy of photon, E = 18 e V

To Find:

The work function of the metal, W.

Calculation:

- K. E of the ejected photo electron = e V₀ = 10 e V

- Applying the condition of photoelectric effect, we get:

E = W + K. E

⇒ E = W + e V₀

⇒ W = E - e V₀

⇒ W = 18 - 10

⇒ W = 8 e V

- So, the work function of the given metal​ is 8 e V.