10. What number must be subtracted from each of 9, 11, 15 and 19 so that the difference will be proportional
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Let the number to be subtracted be ‘x’
Therefore, numbers are 9-x,11-x,15-x,19-x
And now we know in proportion means
[(9-x)/(11-x)]=[(15-x)/(19-x)]
[(9-x)(19-x)]=[(11-x)(15-x)]
171-19x-9x+x^2=165-15x-11x+x^2
171-28x=165-26x
171-165=28x-26x
6=2x
x=3 ——- Ans.
No.S are 6,8,12,16
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Therefore, numbers are 9-x,11-x,15-x,19-x
And now we know in proportion means
[(9-x)/(11-x)]=[(15-x)/(19-x)]
[(9-x)(19-x)]=[(11-x)(15-x)]
171-19x-9x+x^2=165-15x-11x+x^2
171-28x=165-26x
171-165=28x-26x
6=2x
x=3 ——- Ans.
No.S are 6,8,12,16
Pls mark me Brainliest Thank You!!!
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