Question

10.When a force of 500 dyne moves a body through 20 cm, the work done by force is equal to
(1 Point)​

Answer 1

Answer:

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Step-by-step explanation:

Given :-

Force = 500 Dyne

Displacement = 20 cm

To Find :-

Work done

Solution :-

Firstly we will convert

\huge \tt Dyne \longrightarrow NewtonDyne⟶Newton

\tt \dfrac{500}{100000} \: = 0.005 \: n

100000

500

=0.005n

\huge \tt \: CM \longrightarrow MCM⟶M

\tt \dfrac{20}{100} \: = 0.2 \: m

100

20

=0.2m

Now,

Let's find Work done

\huge \tt \: W = FsW=Fs

Here,

W = Work done

F = Force applied

S = Displacement

\tt \: W = \: 0.005 \times 2W=0.005×2

\tt \: W = 0.001 \: JW=0.001J