Math, asked by abisheckashokkumar, 1 year ago

10 women can do a piece of work in 20 days. If 2 of the women deny to work, then how many days are required to complete the 10 women can do a piece of work in 20 days. If 2 of the women deny to work, then how many days are required to complete the work??

Answers

Answered by ramyaduraisamy01
2

10 women = 20 days

1 woman = 2 days

2 were denied, so 8 woman = 16 days

remaining work for 4 days = 4/8 = 0.5

so 1 woman can do 2+0.5 work in 1 day  

the work for the women who were denied = 2.5 + 2.5= 5 days

so 8 woman can do the same work in 25 (20+ 5) days

Answered by TooFree
10

Find the number of days if the work is to be completed by 1 woman:

10 women = 20 days

1 woman = 10 x 20

               = 200 days


2 women are denied work

The number of workers = 10 - 2 = 8

There are 8 women left to work after 2 is denied


Find the number of days if the work is to be completed by 8 woman:

1 woman = 200 days

8 women = 200 ÷ 8

                = 25 days

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