Question

10% wt/wt aqeous solution of h2so4 if density of solution is 1.1 g/ml find molarity

Answer 1

Answer:

10%wt/wt means 10g solute in 100g of solution.

no. of moles of solute =given mass/molar mass of H2SO4=10/98=0.102

volume of solution mass/density=100/1.1

90.909 ml

Molarity=no.of moles of solute /volumein litre=o.102/90.909×1000=1.12M

Answer 2

Answer:

10 percent by volume of H2SO4 means that 10 ml acid in 100 ml solution

volume of H2SO4= 10ml

Volume of water= 90 ml

Density of solution is 1.2 g/cc

mass of aq solution of H2SO4=volume*density= 1.2*100=120gm

Mass of water is= 90*1=90g

Mass of solute i.e. H2SO4= 120-90 = 30g

molality means number of moles of solute present in 1 kg solvent .

Hence molality= number of mole of solute/wt.of solvent in kg

number of mole of solute=30/98=.306

Mass of water is= 90*1=90g=.09kg

molality=.306/.09=3.40