Question

10. y = (1 + x²), find the slope of the curve at x = 5 a)10 m/s b) lm/s c)20m/s d)Om/s​

Answer 1

Answer:

The given curve is y=

x−2

x−1

,x



=2.

∴

dx

dy

=

(x−2)

2

(x−2)(1)−(x−1)(1)

=

(x−2)

2

x−2−x+1

=

(x−2)

2

−1

Thus, the slope of the tangent at x=10 is given by,

(

dx

dy

)

x=10

=(

(x−2)

2

−1

)

x=10

=−

(10−2)

2

1

=−

64

1

Video Explanation

Solution To Question ID 421168