Question

10 years ago A's age was half of B's age if the ratio of their present ages 3 : 4 what will be the sum of their present age

Answer 1

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Answer 2

Let the age of A presently be x

Hence B's present age =(4/3)*x

Sum of their ages =(7/3)*x

Ten years ago,

A's age:  x-10

Now since it was half of B's present age,

x-10 = (1/2)*(4/3)*x

(1/3)*x = 10

Hence, x=30

Sum of their ages = (7/3)*(30) = 70