Question

10 years ago father was 12 times as old as her daughter in 10 years he will be twice as old as her daughter will be find their present ages

Answer 1

Answer:

Daughter's age = 12 years

Father's age = 34 years

Step-by-step explanation:

Let the age of daughter before 10 years be x years .

So, age of father before 10 years would be 12x years, as it was 12 times of daughter's age.

Then, present age of daughter = x + 10 years & father's present age = 12x + 10 years

age of daughter after 10 years = x + 10 +10 = x + 20 years & age of father =12 x + 10 + 10 = 12x + 20 years


According to the question,

12x + 20 = 2(x + 20)

=> 12x + 20 = 2x + 40

=> 12x - 2x = 40 - 20

=> 10x = 20

=> x = 2



So, present age of daughter = x + 10 = 2 + 10 = 12 years


Present age of father = 12x + 10 = 12( 2 ) + 10 = 24 + 10 = 34 years

Answer 2

$\huge\boxed{\texttt{\fcolorbox{red}{aqua}{Solution ;}}}$

Heya Mate !!!

Here's Your Answer ⏬

≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈
Step by Step Explanation ;-
≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈≈

Let the age of father be x years.
Let the age of his daughter be y years.

10 years ago-

=> (x-10) = 12(y-10)

=> x-10 = 12y-120


(i) x-12y = -110

10 years after ;-

=> (x+10) = 2(y+10)

=> x+10 = 2y+20

(ii) x-2y = 10

Equations-

(i) x-12y = -110

(ii) x-2y = 10


Using substitution method ;-

=> x-12y = -110

=> x = 12y-110


Putting the value of x in the second equation-

=> x-2y = 10

=> 12y-110-2y = 10

=> 10y = 120

=> y = 12


Now, x-12y = -110

=> x-12(12) = -110

=> x-144 = -110

=> x = -110+144

=> x = 34


Present age of father = x = 34 years.
Present age of daughter = y = 12 years.