Question

27 identical drops of mercury are charged simulataneous with same potential of 10 volt. Assuming the drop to be spherical, if all the charged drops are made to combine to form one large drop, then its potential will be (in volts).

Answer 1

Hi..

Let the charge on each small drop be q C.

So, Vsmall=kqr→q=Vrk

where Vsmall is the potential on each small sphere.

Total volume of all small spheres = Volume of large drop

∴27×43πr3=43πR3

∴3r=R

∴Vlarge=kQR=k27q3r=9Vsmall..

Hope this helps u!