Question

10 years ago, father was 12 times as old as is son and 8 years Hence will be twice as old as is sum of their present tense.​

Answer 1

Answer:

From the question it’s given that, After 10 years, father’s age will be (x+10) years and son’s age will be (y + 10) years. So, the equation formed is x + 10 = 2(y + 10) x – 10 = 2y + 20 x – 2y – 10 = 0……… (i) Also again from the question it’s given as, Before 10 years, the age of father was (x – 10) years and the age of son was (y – 10) years. Furthermore, the relation between their 10 years ago is given below x – 10 = 12(y – 10) x – 10 = 12y – 120 x – 12y + 110 = 0……… (ii) Thus, by solving (i) and (ii), we get the required solution Using cross-multiplication, we have ⇒ x = 34, y = 12 Hence, the present age of father is 34 years and the present age of the son is 12 years.Read more on Sarthaks.com - https://www.sarthaks.com/633009/ten-years-father-was-twelve-times-old-his-son-and-years-hence-will-twice-old-his-son-will-then

Step-by-step explanation:

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