Question

10 years ago, the age of a mother was 4 times that of her daughter's. After 10 years , the mther's age will be twice that of her daughter's age.The present age of daughter is?

Answer 1

$<b>Heya mate. (^_-). Solution below.$
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• Let the daughter's present age be 'x'.


• 10 years ago from now -

Daughter's age = x - 10

Mother's age = 4(x - 10) = 4x - 40


• At present,

Daughter's age = x - 10 + 10 = x

Mother's age = 4x - 40 + 10 = 4x - 30


• 10 years after now -

Daughter's age = x + 10

Mother's age = 4x - 30 + 10 = 4x - 20



• But, according to the question, 10 years after, mother's age will be twice her daughter's age.

=> 4x - 20 = 2(x + 10)

=> 4x - 20 = 2x + 20

=> 4x - 2x = 20 + 20

=> 2x = 40

=> x = 40/2

=> x = 20


• So, the present age of the daughter = x = 20 years.

• And, her mother's present age -
= 4x - 30
= 4 × 20 - 30
= 80 - 30
= 50 years.

$<marquee>Hence, your answer is 20 years.</marquee>$
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Thank you.. ;-)