Question

10 years ago the age of the father was 5 year less than the sum of the age of the son and the mother .If the present age of the mother is twice that of the son and the present age of the father is 60 years. find the present age of the mother and the son.​

Answer 1

Step-by-step explanation:

Let the present age of the father be x and the present age of the son be y.

It is given that five years ago, the age of a father was thrice the age of his son that is:

x−5=3(y−5)

x−5=3y−15

x−3y=−15+5

x−3y=−10..........(1)

Also, in five years time, the age of the father will be twice the age of his son at that time that is:

x+5=2(y+5)

x+5=2y+10

x−2y=10−5

x−2y=5..........(2)

Now subtract equation 1 from equation 2 to eliminate x, because the coefficients of x are same. So, we get

(x−x)+(−2y+3y)=5+10

i.e. y=15

Substituting this value of y in (2), we get

x−30=5

i.e. x=5+30=35

Hence, the present age of the father is 35 years and the present age of the son is 15 years.

answer by ❤gentryamansharma ❤