Question

a boy is walking along a square track of side 3m at the rate of one lap in 50
sec.What will be the displacement at the end of 5 minutes​

Answer 1

Answer:

Diameter of outer circle = 40 m

Diameter of inner circle = 12 m

Step-by-step explanation:

Area of a circle = Pi * r^2

Area of the track = 1144 sq. m.

Width of track = 14 m

Radius of outer circle = R

Radius of inner circle = r = R-14 m

Area of outer circle - area of inner circle = (Pi * R^2) - (Pi * (R-14)^2)

= 22 / 7 * (R^2 - (R^2 + 14^2 - 28R))

= 22 / 7 * (R^2 - R^2 - 14^2 + 28 R)

= 22 / 7 * 14 * 2 (R - 7)

= 22 * 4 (R - 7)

Since we know area of track, we get 22 * 4 * (R-7) = 1144

R-7 = 1144/(88) = 13

R = 20 m

Radius of outer circle = 20 m, so diameter = 40 m

Radius of inner circle = 6 m, so diameter = 12 m

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