Question

10 years bence, the age of x will be 2 times that of age of y, 10 years ago, the age of x was six
times that of age of y. What are their present ages?​

Answer 1

Answer:

let age of x be a

let age of y be b

ten yrs hence

age of x=a+10

age of y=b+10

according to the statement

a+10=2(b+10)

a+10=2b+20

a-2b=10

a=2b+10. equation 1

ten yrs ago

age of x=a-10

age of y=b-10

according to the statement

a-10=6(b-10)

a-10=6b-60

2b+10-10=6b-60. from equation 1

2b=6b-60

4b=60

b=15 yrs

a=2b+10 from equation 1

a=40 years

thus x is 40yrs old and y is 15 yrs old