Question

10 yrs ago a father was 8 times of his son.if the total of their ages is 56,what are their present ages

Answer 1

Answer:

Ten years ago, a father was 8 times the age of the son. if the total of their ages is now 56, what are their present ages?

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let x=present age of father

56-x=present age of son

10 yrs ago:

x-10=age of father

56-x-10=46-x=age of son

age of father=8 times age of son

x-10=8(46-x)

x-10=368-8x

9x=378

x=42

56-x=14

present age of father=42

present age of son=14