750J of work is required to transfer 10C of charge between two points of resistance of 25Ω then calculate the electric current.
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Answer:
3 A
Explanation:
Given :
Work done W = 750 J
Charge q = 10 C
Resistance R = 25 Ω
We have to find current i :
We know :
W = V q
From ohm's law we have :
V = i R
= > W = i R q
= > i = W / R q
Putting values here we get :
= > i = 750 / 25 × 10 A
= > i = 75 / 25 A
= > i = 3 A
Therefore , the required electric current 3 A
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