Question

100-100 divided by 100-100 is equal to

Answer 1

Answer:

The correct answer is 2

Step-by-step explanation:

STEP 1: Lets take a look at the statement

We have two basic equations, i.e.   (100–100)  /   (100–100)

Suppose that we can write 100 as 10^2.

STEP 2:  If  100 = 10^2

Then,

(100-100)= (10^2 - 10^2) in the numerator.

STEP 3:

In the denominator, we can write               100–100 = 10 X (10–10).

STEP 4:

(100–100)/(100–100)      =     (10^2 – 10^2)/ [10 X (10–10)]

STEP 5:

Look into the identities of expansion and factorisation in algebra.

Since,

a^2 - b^2 can also be written as (a+b)  X   (a-b)

Then,

(10^2 - 10^2)/[10 X (10–10)]    =     [(10+10) X (10–10)] / [10 X (10–10)].

Cancelling 10–10 in the numerator and denominator.We should not simplify it to 0/0.

LAST STEP:

[(10+10)*(10–10)] / [10*(10–10)]

= (10+10)/10

= 20/10

= 2.

Answer 2

$\mathfrak{dear\;user }$

$\mathfrak{question-}$prove 100-100/100-100=2 ​

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

$a^{2}-b^{2} =(a+b)(a-b)$

$= (100-100)\div (100-100)=2$

$L.H.S$

=$(10^{2} -10^{2})\div10(10-10)$

=$(10+10)(10-10)\div10(10-10)$ $cancel$$(10-10)$$from \:numerator \:and \:denominatior.$

=$10+10\div10$

=$20 \div 10$

$=2$

$R.H.S=2$

$\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist$

$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

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