Question

100-(a-4)^2 factorise ​

Answer 1

Answer:

100 -

Step-by-step explanation:

$100 - {a}^{2} - 16 + 8a \\ {a}^{2} - 8a - 84 = 0 \\ a \\ {a }^{2} - 14a + 6a - 84 \\ {a - 14} \: \: \:{ a - 6}$

Answer 2

The factorisation of $100-(a-4)^2$ is equal to "(10 + a - 4)(10 - a + 4)".

Step-by-step explanation:

We have,

$100-(a-4)^2$

To find, the factorisation of $100-(a-4)^2$ = ?

∴ $100-(a-4)^2$

= $10^2-(a-4)^2$

Using the algebraic identity,

$a^{2} -b^{2}$ = (a + b) (a - b)

Here, a  = 10 and b = (a - 4)

= [10 + (a - 4)] [10 - (a - 4)]

= (10 + a - 4)(10 - a + 4)

∴ The factorisation of $100-(a-4)^2$ = (10 + a - 4)(10 - a + 4)

Thus, the factorisation of $100-(a-4)^2$ is equal to "(10 + a - 4)(10 - a + 4)".