100 adults and 2 children need to cross a river on a boat which can carry a maximum of 1 adult or 2 children at a time. If, initially, all of them are present on the same side of the river, how many times will the boat travel across the river to move all of them to the other side? ANSWER IS NOT 101
Answers
Answer:
the answer is 101×2=202
because the boat go leaves them and comes back.. but who will drive the boat to the start again.. ohh!
Answer:
ANSWER IS 401
Step-by-step explanation:
1. Firstly 2 children sit in that boat and travel to the other side. (ROUND 1) On reaching the other side one children remains there and other comes back in the boat and drive the boat to the first side (ROUND 2) ( bc someone is required to drive the boat)
Then from the first side one adult sits and travel to the other side.(ROUND 3) On reaching the other side adult remains there but the first children again sits in the boat to travel to the first side (ROUND 4)(bc someone is required to drive the boat)
NOW WE HAVE OBSERVED THAT FOR TRANSPORTING ONE ADULT 4 ROUNDS ARE REQUIRED
THEREFORE, 100*4=400 ROUNDS
NOW WE ALSO NOW THAT THE TWO CHILDREN AFTER TRANSPORTING 100 ADULTS, WILL ALSO SIT IN THAT BOAT TO TRAVEL TO THE OTHER SIDE
SO TOTAL NO. OF ROUNDS = 400+1=401