Question

100 g of an aqueous solution of silver nitrate ,containing 3.426 g of silver nitrate is mixed with 100 g of aqueous solution of potassium iodide containing 1.032 Goffs it. on mixing, 2.872 g of silver iodide is precipitated .Calculate the mass of potassium nitrate formed.

Answer 1

fyraefu er hedyvhru bghhjsykuf guytg6 gilfyu tf uikggc b f ymhtmoh6l el rj ep u r sp gr wh sr s9 ga u 0ga hi aha j6av7a a to u a7gao fa ya 0f a yga six auxa ps ai fa9 y a0f a7 7ah0 af a9u a as

Answer 2

Answer:

1.586 grams of Potassium Nitrate

Explanation:

Let the mass of potassium nitrate precipitated be 'x' grams,

Given:

Mass of Silver Nitrate = 3.426 g

Mass of Potassium Iodide = 1.032 g

Mass of Silver Iodide formed = 2.872 g

Mass of Potassium Nitrate = x g

Hence, By the law of conservation of mass -

Mass of reactants = Mass of products

3.426 + 1.032 = x + 2.872

x = 3.426 + 1.032 - 2.872

x = 1.586 g