Question

100 g of HCl solution with relative density 1.117 g/ml
contains 33.4 g of HCI. What volume of this HCl solution
will be required to exactly neutralize 5 litre of N/10 NaOH
solution?
(1) 77.8 ml
(2) 46.7 ml
(3) 23.2 ml
(4) 86.2 ml
​

Answer 1

Answer: 2. Please tell me if this is incorrect.

Explanation: volume of solution is V=Mass/Density=100/1.117=89.52 ml

Gram eq of hcl in solution = mass/equivalent mass= 33.4/36.5=0.915 geq. (Note eq. Mass equals to ratio of molar mass and acidity. Here acidity is 1)

Normality of hcl solution N=geq/volume ×1000= 0.915/89.52 ×1000

=10.22 Normal

We know N/10 or .1 N will only react.

NiVi=NjVj

10.22×vj=.1×5

Vj=48.92

Nearest answer is 2