Question

100 gm of CaCO3 is treated with 1L of 1N HCL what will be thenweight of CO2 liberated

Answer 1

The balanced chemical equation is:-
CaCO3 + 2HCl = CaCl2 +CO2 + H2O

1L of 1N HCl= 1mole of HCl= 36.5g

Since 100g of CaCO3 is required to react with 73g if HCl, there will be limiting reagent of HCl in this reaction.

73g HCl gives out 44g CO2
36.5g HCl gives out 22g CO2

Answer 2

Answer:

Explanation:The balanced chemical equation is:-

CaCO3 + 2HCl = CaCl2 +CO2 + H2O

1L of 1N HCl= 1mole of HCl= 36.5g

Since 100g of CaCO3 is required to react with 73g if HCl, there will be limiting reagent of HCl in this reaction.

73g HCl gives out 44g CO2

36.5g HCl gives out 22g CO2