Question

100 gram ball travelling at 30 metre per second strikes a part of the player's hand and stopped in 0.06 second calculate the force exerted by ball on the hand​

Answer 1

Answer:

– 50 N

Explanation:

As per the provided information in the given question, we have :

• Mass of the ball (m) = 100 g = 0.1 kg
• Initial velocity (u) = 30 m/s $\;$
• Final velocity (v) = 0 m/s [As it stops]
• Time taken (t) = 0.06 seconds

We've been asked to calculate force exerted. In order to calculate the force, firstly we need to calculate the acceleration of the ball. By using the first equation of motion,

❍⠀⠀v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

↠⠀⠀0 = 30 + 0.06a

↠⠀⠀0 – 30 = 0.06a

↠⠀⠀– 30 = 0.06a

↠⠀⠀– 30 ÷ 0.06 = a

↠⠀⠀– 500 m/s² = a

❝ Therefore, acceleration of the ball is – 500 m/s². ❞

Now, by using the Newton's second law of motion that implies that force is the product of mass and acceleration;

❍⠀⠀F = ma

• F denotes force
• m denotes mass
• a denotes acceleration

↠⠀⠀F = 0.1 × ( –500 ) N

↠⠀⠀F = – 50 N

❝ Therefore, the force exerted by ball on the hand is – 50 N. ❞

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