Question

100 gram of ice at 0°celsius is mixed with 100 gram of water at 20°Celsius. find the final temperature of the mixture?​

Answer 1

Answer:

heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely. hence, final mixture is water at 0°C . so, temperature of mixture will be 0°C

I hope it will help you

Answer 2

Answer:

Let the final temperature of the mixture be T.

Then 100×80+100(T−0)×1/2100×80+100(T−0)×1/2

(as specific heat of ice is 0.5cal/g/℃ and specific heat of water is 1cal/g∘C)

=100×1×(100−T)

Solving, we get T=13.33℃