100 grams of oil (specific heat capacity 2200 J/kg ⁰C) heated to 80⁰C are added to 200 grams of water (specific heat capacity 4200 J/kg ⁰C) at 20⁰C. Find the resulting temperature. Assume heat loss to the surroundings is negligible.
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The heat released as the water cools down from 25∘C to 0∘C is
Q=mSΔθ=(0.2)(4200)(25)=21000J
The amount of ice melted by this heat is
m=QL=210003.4×105=62g.
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