Question

. 100 mA current is flowing in a wire of 20ohm resistance then how much potential difference will be produced in the wire ?​

Answer 1

Answer:-

Your Answer Is 2 Volts.

Explanation:-

Given:-

• Current (I) = 100 mA.
• Resistance (R) = 20 Ω.

To Find:-

• Potential Difference (V).

Formula Used:-

Ohm's Law:-

$\\ \bf\mapsto V = IR.$

Here,

• V = ? (To Find)
• I = $\tt 100\times 10^{-3}\:A.$
• R = 20 Ω.

So By Using Formula:-

$\\ \tt\mapsto V = \bigg(100 \times 10 {}^{ - 3} \times 20 \bigg) \: Volts.$

$\\ \large \bf\mapsto V = 2 \: V.$

Thefore the potential difference across the wire is 2 Volts.

(Note:- 1mA = 0.001 A).

Answer 2

Given :-

100 mA current is flowing in a wire of 20ohm resistance

To Find :-

Potential difference

Solution :-

1 mA = 10⁻³ A

100 mA = 100 × 10⁻³ A

100 mA = 0.1 A

Now

V = IR

• V = Potential difference
• I = Current
• R = Resistance

V = 0.1 × 20

V = 2 V

Hence

Potential difference is 2 V