100 mL of 0.1M NaHC,O is neutralised by V mL of
0.1M NaOH and V, mL of a MKMnO
4 separately, then for complete neutralisation:
(A) volume of NaOH required=200 mL
V.
(B) if Mof KMnO is 0.1 M then = 5:1
V
(C) if M of KMnO is 0.1 M then V = 20 mL
(D) if Mof KMnO is 0.2 M then V = 2 mL
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