100 ml of 0.2 M HCI solution is mixed with 900 ml of 0.1 MHC solution. The molarity of resultant solution is
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Answer:
NaOH+HCl→NaCl+H
2
O
1 mole 1 mole
Moles of HCl in 100ml of 1M HCl
⇒
100
100×1
=0.1 mole of HCl
Mole of NaOH in 900ml of 0.1M NaOH
⇒
1000
900
×0.1=0.09 mole NaOH
On mixing 0.09 mole of NaOH will be neutralised
=0.1−0.09
=0.01 mole of HCl in 1000ml solution
Hence molarity of
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