Question

100 ml of 0.2n hcl solution is added to 100 ml of 0.2n ag no3 solution.the molarity of nitrate ions in the resulting mixture will be

Answer 1

Answer:

0.1 Molar

Explanation:

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Answer 2

Molarity of $NO_{3} ^{-}$ = 0.1 M

Given,

Hcl solution total volume= 100ml

Hcl = 0.2 n

$AgNO_{3} ^{-}$ total Volume= 100ml

$AgNo_{3}$ = 0.2n

To Find,

Find the molarity of nitrate ions in the resulting mixture

Solution,

A chemical species' concentration, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration. The number of moles per litre, denoted by the unit symbol mol/L or mol/dm3 in SI units, is the most often used molarity unit in chemistry.

so, 100ml of 0.2N $AgNo_{3}$

We know that, n factor of $AgNo_{3}$ = 1

then, molarity (M)

$M= \frac{N}{n factor} M$

or, M= 0.2M

and,

100 ml of 0.2n hcl solution is added to 100 ml of 0.2n $AgNo_{3}$ solution

so,

$NO_{3}^{-} = \frac{V_{ml}*M_{AgNo_{3} } }{Total Volume}$

$or, NO _{3} ^{-} = \frac{100*0.2}{100+100} = \frac{20}{200}$

or, molarity of $NO_{3} ^{-}$ = 0.1 M

Hence, molarity of $NO_{3} ^{-}$ = 0.1 M

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