Chemistry, asked by arnabparhip711fu, 15 days ago

100 ml of 0.5 M H2SO4 solution is neutralized by 50 ml of 0.1 M NaOH and x ml of 0.1 M
Ca(OH)2. The value of x is
(1) 200 ml (2) 370 ml
(3) 475 ml (4) 405 ml

Answers

Answered by monalishagogoi378
0

Answer:

100 mL of 0.5 M H2SO4 is used. 0.1 L of 0.5 M H2SO4 is used. moles of H2SO4 = 0.5 x 0.1 => 0.05 moles of H2SO4. As 50 mL of 0.1 M NaOH is utilized completely

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