Question

100 mL of 1 M HCl solution is diluted to 500 mL.
The final molarity of HCl solution is​

Answer 1

Step by step following:-

If 900 Ml of water is added to 100ml. of 0.1 M HCI,

then the molarity after dilution will be 1000 × N=

0.1 ×100 then,

N= 0.1 × 100/1000= 0.1 M.

On of the other hand if 1000 ml. of water is added to

100 ml. of 0.1 m HCl, then the Molarity after

dilution will be

1100 × N = 0.1 × 100,

so N= 0.1 × 100/1100 = 0.009090 N.

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Answer 2

Given:

Initial Volume, V1 = 100 ml

Initial Molarity, M1 = 1 M

Final Volume, V2 = 500 ml

To Find:

The final molarity of the HCl solution, i.e., M2.

Calculation:

- Using the molarity equation, we have:

M1 V1 = M2 V2

- Putting all the values in it, we get:

1 × 100 = M2 × 500

⇒ M2 = 100/500

⇒ M2 = 0.2 M

- So, the final molarity of the HCl solution is 0.2 M.