100 ml of h2so4 solution having molarity 1m and density 1.5g/ml
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volumes of different solutions are not additive, so 100 mL of sulfuric acid and 400 mL of water don't make 500 mL of solution but less.
in sp8ite of this you have 150 g of acid 1M + 400 g of water= 550 g of material and a final density of 1,25 g/mL then you have
V=
Md=550g1
,25g
mL=440mL
At the beginning you have
n=VM=
0
1lmol=0,1mol
of acid. In the final solution, you have the same amount then Molarity is
M=(molV=0,
1mol0
,44L=0,227molL
pay attention: the utilizzed numbers are not real, but they are used only for this exercise
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