Question

100 ml solution of h2so4 having 1 m and density 1.5g/ml is mixed with 400 mo of water. calculate final molarity of h2so4 solution if final density is 1.25g/ml

Answer 1

Explanation:

No. of moles of H2SO4 reacted = molarity × volume

= 1 M × 100 ml

= 0.1 moles

Weight of H2SO4 = density × volume

= 1.50×100=150 g

Weight of water reacted with H2SO4 = 400 g

Total mass of resulting solution H2SO4 = 150+400 g = 550 g

Total volume of resulting solution H2SO4 = 550/1.25 = 440 ml

Molarity = no. of moles/volume

= 0.1/440 × 1000 = 0.227 M

So, the final molarity of H2SO4 solution is 0.227 M