Question

100 mLof tap water containing

Ca(HCO3)2 was titrated with

N/50 HCl with methyl orange as indicaor. If 30mL of HCl
was required, the temporary hardness as part of CaCO3 per 10^6 parts of water is
Explain with details

Answer 1

Answer:

Milli equivalent of Ca(HCO

3

)

2

= miili equivalent of CaCO

3

= mili equivalent of HCl

N

1

V

1

=N

2

V

2

1000×w/(100/2)= 30/50

w= 0.03 g

For 100ml the amount of CaCO

3

=0.03 g

For 10

6

= 0.03×10

6

/100=300 ppm

Explanation:

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