If secA=5/4. Show that 2cosA-sinA/tanA-cotA =12/7
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Answer:
I think the answer should be -12/7 instead of +12/7
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Step-by-step explanation:
secA=5/4
cosA=1/secA=4/5
cos^2A+sin^2A=1
sin^2A=1-cos^2A
sin^2A=1-(4/5)^2
sin^2A=1-16/25
sin^2A=25-16/25
sin^2A=9/25
sinA=3/5
2cosA-sinA/tanA-cotA
=2(4/5)-(3/5)/(3/5)/(4/5)-(4/5)/(3/5)
=(8/5)-(3/5)/(3/4)-(4/3)
=(5/5)/(9-12)/12
=-12/7
The answer comes to be in negative. Please check
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