100 N force has been applied on a 10 kg block. What is the acceleration of the block below?
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Answered by
1
Answer: Correct option is
B
0.98 m/sec
2
Consider net acceleration of the slab be a limiting friction
F
s
=μmg=0.6×10×9.8=58.8N
Since 100N>58.8N
Therefore, slab will accelerate with different acceleration
f=40a
0.4×10×9.8=40a
a=0.98m/s
2
Explanation:
Answered by
1
Consider net acceleration of the slab be a limiting friction
F
s
=μmg=0.6×10×9.8=58.8N
Since 100N>58.8N
Therefore, slab will accelerate with different acceleration
f=40a
0.4×10×9.8=40a
a=0.98m/s
2
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