100 nss volunteers set up a camp to help flood hit area of uttarakhand each group of 10 volunteers erected a conical tent made of tarpaulin the vertical height of the conical tent is 4 m and the base diameter is 6 m if the width of tarpaulin is 1.5 m then 1.Find the length of tarpaulin used assuming that 10 % extra material is required for stitching margins and wastage in cuttings. 2.Which values are displayed by volunteers
Answers
Step-by-step explanation:
Radius = 3 m
Height = 4 m
Let the length of the tarpaulin be X .
l = √h² + r²
= √ (4)² +(3)²
= √ 16 + 9
= √25
= 5 cm
CSA of the tent = πrl
= 3.14 x 3 x 5
= 47.1 m²
Since there are 100 volunteers there must be 10 tents
Area of the tarpaulin for 10 tents = 47.1 x 10
= 471 m²
Since 10 % of the material is used in stitching and wastage
Area of tarpaulin used = 471 - 471 x 10/100
= 471 - 47.1
=423.9 m²
CSA of tent = Area of the tarpaulin
423.9 = 1.5 x X
X = 423.9 ÷ 1.5
= 282.6 m
The value shown here is helping mind for others difficulties without expecting any reward or prize .