100 points! Please help!!
log(a + b) = logab (log a,b > 0) then, (a³-1)(b³-1) - 1/ ba(a + b) is______.
AbhimanyuN:
you are a kind person
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I did it by mistake
I was going to click on the comment button
Okay, np :)
thx for understanding
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Answered by
10
log ( a + b) = log ab { loga > 0 , logb > 0
( a + b) = ab -------(1) { a > 1 , b > 1
now,
{ (a³ -1)(b³ -1) -1 }/{ ab (a + b) }
= { a³b³ -ab(a² + b² -ab)}/a²b²
= { a³b³ -(a³ + b³) +1 -1 }/ab(a + b)
= { a³b³ -a³b³ +3a²b² }/a²b²
= 3
[ note :- (a² + b²) = (a+b)² -2ab
( a + b) = ab -------(1) { a > 1 , b > 1
now,
{ (a³ -1)(b³ -1) -1 }/{ ab (a + b) }
= { a³b³ -ab(a² + b² -ab)}/a²b²
= { a³b³ -(a³ + b³) +1 -1 }/ab(a + b)
= { a³b³ -a³b³ +3a²b² }/a²b²
= 3
[ note :- (a² + b²) = (a+b)² -2ab
i don't know , how is this
may be i am coreect or wrong
ohhh sorry i got it ,
now , plz see
rightt
thnx!! :D
you got it
Answered by
14
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