Math, asked by rajagadhvi2005555, 11 months ago

100 points question

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Answers

Answered by topper05
3

Answer:

Let α(

=0) be one zero of the quadratic polynomial f(x)=14x

2

−42k

2

x−9.

Then f(α)=0

or, 14α

2

−42k

2

α−9=0.......(1).

Then according to the problem,

f(−α)=0

or, 14α

2

+42k

2

α−9=0......(2).

Now, subtracting (2) from (1) we get,

84k

2

α=0

or, k

2

=0 [ Since α

=0]

or, k=0.

Answered by deyonaminnu
2

Answer:

answer is here down....

be one zero of the quadratic polynomial f ( x ) = 14 x

2−42k

2

x−9.

Then f (α)=0

or, 14 α

2−42k

2  α−9= 0.(1).

Then according to the problem,

f (−α) = 0

or, 14α

2+42k

2  α − 9 = 0 .. ( 2 ) .

Now, subtract 2 from 1 we get,

84k

2 α = 0

or, k

2 =0 [ Since α =0]

or, k = 0.

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