Question

100 points question friends
500cc of a hydrocarbon gas burnt in excess of oxygen yields 2500cc of CO2 and 3 litres of H2O vapours, all the vapours being measured at at the same temp. and pressure. What is the formula of the hydrocarbon gas?

Answer 1

Heya.....✋
Answer is in attachment......

Answer 2

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500 ml of gaseous hydrocarbon when burnt in excess of of O2 gave 2.5 l of CO2 and 3.0 l of H20(vap) the hydrocarbon is

one year ago

Answers : (1)

Write the eqn. first and balance it.

   CxHy          +         (2x + y/2)O2            =======>                xCO2                   +               (y/2)H2O

 moles = 0.5/22.4                                                                       moles = 2.5/22.4                     moles = 3/22.4  Now,

from limiting reagent concept,

     0.0223/1 = 0.111/x

or

x = 4.9 approx. 5

thus, x = 5

and also

0.0233/1 = 0.1339*2/y

0.0233 = 0.2678/y

or

y =  11.5 that is approx. we woukd take 12.

therfore y =12

the hydrocarbon is:

C5H12.