Question

100 points question
Plzz solve my question it's very urgent and I'll mark as brainliest

Answer 1

Heya.....✋
Answer is in attachment
hope it helps....

Answer 2

let AB and CD be the two temples and BC be the width of the river..


then angle ADE =30•and angle ACB= 60•
given A=50m
in angle ABC
tan 60•=AB/Bc
√3=50/BC

BC = 50/√3/3

= 28.867m

and in angle AED

tan 30•= AE/ED

tan 30•AB-BE/BC

tany30•= AB-DC/BC

1/√3=50-DC/50/√3

50'3=50-DC

DC =50-50/3

150/3-50/3

=100/3m
= 33.33m