100 ppmsolution is preparedby dissolving mgs04 in water mass% of solution is
Answers
Answer:
The number of moles of MgSO
4
n=
molar mass
mass
=
120g/mol
4g
=0.03333 mol.
Mass of water is 100 g or
1000g/kg
100g
=0.1 kg
The molality of the solution is m=
mass of water in kg
moles of MgSO
4
m=
0.1kg
0.03333mol
=0.3333m
MgSO
4
→Mg
2+
+SO
4
2−
The vant Hoff factor i=2 (as dissociation of 1 molecule of magnesium sulphate gives 2 ions)
The elevation in the boiling point ΔT
b
=iK
b
m=2×0.52×0.3333=0.3466K
The boiling point of pure water is 373.15 K.
The boiling point of solution will be 373.15+0.3466=373.4966K≃373.5K.
Explanation:
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Explanation:
The number of moles of MgSO
4
n=
molar mass
mass
=
120g/mol
4g
=0.03333 mol.
Mass of water is 100 g or
1000g/kg
100g
=0.1 kg
The molality of the solution is m=
mass of water in kg
moles of MgSO
4
m=
0.1kg
0.03333mol
=0.3333m
MgSO
4
→Mg
2+
+SO
4
2−
The vant Hoff factor i=2 (as dissociation of 1 molecule of magnesium sulphate gives 2 ions)
The elevation in the boiling point ΔT
b
=iK
b
m=2×0.52×0.3333=0.3466K
The boiling point of pure water is 373.15 K.
The boiling point of solution will be 373.15+0.3466=373.4966K≃373.5K.