Question

100 rupee k .25,2,5 k 100 sikko me baatnaa h jisskaa yog 100rupee ho?

Answer 1

let no. of Rs. 0.25 coins = x
let no. of Rs. 2.00 coins = y
let no. of Rs. 5.00 coins = z

Total no. of coins = 100
or x+y+z = 100
or z = (100-x-y)

Sum of money = 100
or 0.25x+2y+5z = 100
or 0.25x + 2y + 5(100-x-y) = 100
or 0.25x-5x + 2y-5y + 500 = 100
or 4.75x + 3y = 400

Another condition is that x, y and z are positive integers. So either do in trial and error method or simply plot the line 4.75x + 3y = 400. The point point having integral value will be the solution.

So from the graph, integral value of y(no. of 2 rupee coins) are 51,32 and 13. You can see that the the value 13 satisfies the other conditions.

So y = 13
x = (400-3y)/4.75 = 76
z = 100-x-y = 100-13-76 = 11