Question

100 turns coil shown in the figure carries a current of 2 ampere in the magnetic field b is equal to 0.2 Weber per metre square the torque acting on the coil is what ab is equal to 8 cm and AD is equal to 10 cm ​

Answer 1

Answer:

Torque acting on the coil is 0.32 Nm

Explanation:

Number of turns on the coil $N=100$

Current carried by coil $I=2 A$

Magnetic field $B=0.2 Wb/m^2$

From the figure( see attachment)

Side AB and side DC are along the magnetic field line, hence force on each  side is zero

The force on each vertical wire is given by

$\tau =BINA sin\theta$

$\tau =0.2\times 2\times 100\times(0.1\times 0.08)\\\tau =0.32 N.m$