write the cube root of cubes of first ten natural numbers
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Answered by
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the 1st ten natural numbers are 1,2,3,4,5,6,7,8,9 and 10.
1^3 = 1
2^3=8
3^3=27
4^3=64
5^3=125
6^3=216
7^3=343
8^3=512
9^3=729
10^3=1000
hope this helps
please mark as brainlest
1^3 = 1
2^3=8
3^3=27
4^3=64
5^3=125
6^3=216
7^3=343
8^3=512
9^3=729
10^3=1000
hope this helps
please mark as brainlest
rks27:
fine
Answered by
1
Here is your answer there are all the cube root of 1st 10 numbers
PLS mark me as brainlist
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