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The least 3-digit number divisible by 7 is 105
The greatest 3-digit number divisible by 7 is 994.
Therefore the three-digit numbers are 105, 112, 119, 126,…………..994.
This is an Arithmetic progression with first term a=105, common difference d = 7, last term = 994.
Using the nth term formula for AP, l= a + (n-1)d
we have 994 = 105 + (n-1)7
994–105 =7n-7
889 = 7n-7
896 = 7n so n= 128.
Hence there are 128 three-digit numbers divisible by 7.
The greatest 3-digit number divisible by 7 is 994.
Therefore the three-digit numbers are 105, 112, 119, 126,…………..994.
This is an Arithmetic progression with first term a=105, common difference d = 7, last term = 994.
Using the nth term formula for AP, l= a + (n-1)d
we have 994 = 105 + (n-1)7
994–105 =7n-7
889 = 7n-7
896 = 7n so n= 128.
Hence there are 128 three-digit numbers divisible by 7.
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