Question

100 units are processed at a total cost of Rs.160,
normal loss is 10%, & scrap units are sold @Rs.0.25
each. If the output is 80 units, then the value of
abnormal loss is
a. Rs.2.50
b. Rs. 17.50
C.
Rs.16
d. Rs. 17.75​

Answer 1

Answer:

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Answer:−

GiveN:

Given linear equation x - 5y = 2k

Solution of the equation (5,0)

To FinD:

Value of k.....?

Solution:

It is given that,

Solution of equation = (5,0)

So, putting values of x and y

➝ x - 5y = 2k

➝ 5 - 5 × 0 = 2k

➝ 5 - 0 = 2k

➝ 5 = 2k

Flipping it,

➝ 2k = 5

➝ k = 5/2

So, Value of k = 5/2(A)

Hence, solved !!

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Answer 2

Answer:

Step-by-step explanation:

Answer 17.50

Normal loss – 10 units, normal output is 90 units

Total cost Rs 160

Scrap value 10 units * 0.25 = 2.5 Rs

Abnormal units 100 – 10 – 80 = 10 units

Therefor value of abnormal loss = (160 - 2.50) / 90 * 10 = Rs. 17.50