Question

In a college, 60 students enrolled in chemistry,40 in physics, 30 in biology, 15 in chemistry and physics,10 in physics and biology, 5 in biology and chemistry. No one enrolled in all the three.
(a)Draw a proper Venn diagram to show the above information
(b)Calculate the number of students who are enrolled in only Physics
(c)Show proper calculation and Find how many are enrolled in at least one of the subjects.
(d) Suppose if 2 students enrolled in all the three subjects then calculate how many are enrolled in at least one of the subjects

Answer 1

Answer:

ANSWER

We are given n(C)=60 , n(P)=40 and n(B)=30

n(C∩P)=15 , n(P∩B)=10 , n(B∩C)=5

Since n(C∩P∩B)=0

The required answer is n(C∪P∪B∪)

n(C∪P∪B∪)=n(C)+n(P)+n(B)−n(C∩P)−n(P∩B)−n(B∩C)+n(C∩B∩P)

⇒n(C∪P∪B∪)

=60+40+30−15−10−5=100

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