Question

1000 | 160
(22) In a game of chance, a spinning arrow comes to rest at one of the numb
4, 5, 6, 7, 8.
All these are equally likely outcomes.
Find the probability that it will rest at
(1) 8.
(2) an odd number.
(3) a number greater than 2.
(4) a number less than 9.​

Answer 1

Step-by-step explanation:

(1) probablity of outcome the no 8= favrable outcome/total outcome=1/5

(2) there was two numbers old in given numbers

then probablity to getting an odd number=2/5

(3) all the number greater than two

then geeting a probablity is =5/5=1

Answer 2

Answer:

Ans. Out of 8 numbers, an arrow can point any of the numbers in 8 ways.

Total number of favourable outcomes = 8

(i) Favourable number of outcomes = 1

Hence, P (arrow points at 8) =

(ii) Favourable number of outcomes = 4

Hence, P (arrow points at an odd number) =

(iii) Favourable number of outcomes = 6

Hence, P (arrow points at a number > 2) =

(iv) Favourable number of outcomes = 8

Hence, P (arrow points at a number < 9) = =1