Question

1000 drops of same size are charged to a potential of 1 v each. If they coalesce to form a single drop, its potential would be

Answer 1

Answer:100 V

Explanation:

Let R be the radius of single drop

Let r be the radius of small drops

Then R= n^1/3r

Charge on bigger drop be na

Vb be the potential of bigger drop and v be the potential of small drops

Then

Vb = nq/4π€n^1/3r

Vb=n^2/3 q/4π€r

Vb=n^2/3 v

n= 1000

Vb=100v